SWUSTOJ #287 one + two = 3

题目

读入两个小于100的正整数A和B，计算A+B。需要注意的是：A和B的每一位数字由对应的英文单词给出。

输入

测试输入包含若干测试用例，每个测试用例占一行，格式为"A + B ="，相邻两字符串有一个空格间隔。当A和B同时为0时输入结束，相应的结果不要输出。

输出

对每个测试用例输出1行，即A+B的值。

样例输入

one + two =

three four + five six =

zero seven + eight nine =

zero + zero =

样例输出

3

90

96

源代码

#include <stdio.h>#include <string.h>int num1(char a[]){if(strcmp(a,"one") == 0) return 1;else if(strcmp(a,"two") == 0) return 2;else if(strcmp(a,"three") == 0) return 3;else if(strcmp(a,"four") == 0) return 4;else if(strcmp(a,"five") == 0) return 5;else if(strcmp(a,"six") == 0) return 6;else if(strcmp(a,"seven") == 0) return 7;else if(strcmp(a,"eight") == 0) return 8;else if(strcmp(a,"nine") == 0) return 9;else if(strcmp(a,"zero") == 0) return 0;}int num2(char a[]){if(strcmp(a,"one") == 0) return 1;else if(strcmp(a,"two") == 0) return 2;else if(strcmp(a,"three") == 0) return 3;else if(strcmp(a,"four") == 0) return 4;else if(strcmp(a,"five") == 0) return 5;else if(strcmp(a,"six") == 0) return 6;else if(strcmp(a,"seven") == 0) return 7;else if(strcmp(a,"eight") == 0) return 8;else if(strcmp(a,"nine") == 0) return 9;else if(strcmp(a,"zero") == 0) return 0;}int main(){char a[20];while(1){int sum=0, sum1=0, sum2=0;scanf("%s", a);sum1=num1(a);scanf("%s", a);if(strcmp(a,"+") != 0){sum1 = sum1*10 + num1(a);scanf("%s", a);}scanf("%s", a);sum2 = num2(a);scanf("%s", a);if(strcmp(a,"=") != 0){sum2 = sum2*10 + num2(a);scanf("%s", a);}sum = sum1 + sum2;if(sum == 0)break;elseprintf("%d\n", sum);}return 0;}

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